The escape velocity of an object on a planet whose radius is 4 times that of the earth and g value 9 times that on the earth, in kms−1 is
A
33.6
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B
67.2
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C
16.8
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D
25.2
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Solution
The correct option is B 67.2 Escape speed is given by, vmin=√2gR which is equal to ≈11.2 km/s on Earth's surface. For another planet with radius 4 times and g value 9 times that of Earth v′min=√2×9g×4R