The escape velocity on a planet is - If the radius of the planet contracts to 14th of present value without any change in its mass- the escape velocity will be-

The correct option is B DoubledEscape velocity on a planet is ν=√(2GM/R) Now the radius of planet contracts to one fourth of present value without change ...

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Standard XII

Physics

Escape Speed

The escape ve...

Question

The escape velocity on a planet is $ν$ . If the radius of the planet contracts to $\frac{1}{4} t h$ of present value without any change in its mass, the escape velocity will be.

Halved

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Doubled

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Quadruped

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Becomes-one-fourth

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Solution

The correct option is B Doubled
Escape velocity on a planet is $ν = \sqrt{\frac{2 G M}{R}}$
Now the radius of planet contracts to one fourth of present value without change in its mass.
So $R^{'} = \frac{R}{4}$
So new escaple velocity $ν^{'} = \sqrt{\frac{2 G M}{R^{'}}} = \sqrt{\frac{4 \times 2 G M}{R}} = 2 ν$

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The escape velocity on a planet is ν. If the radius of the planet contracts to 14th of present value without any change in its mass, the escape velocity will be.

The correct option is B DoubledEscape velocity on a planet is ν=√2GMRNow the radius of planet contracts to one fourth of present value without change in its mass. So R′=R4So new escaple velocity ν′=√2GMR′=√4×2GMR=2ν

The escape velocity on a planet is $ν$ . If the radius of the planet contracts to $\frac{1}{4} t h$ of present value without any change in its mass, the escape velocity will be.