The esterification of acetic anhydride by ethyl alcohol can be represented by the following balanced equation- A C H 3 CO 2 O - B C 2 H 5 OH - CH 3 COO C 2 H 5 - CH 3 COOHWhen the reaction is carried out in dilute hexane- rate is k -A-B- When ethyl alcohol is the solvent- rate is k -A-Explain the difference-

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The esterific...

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The esterification of acetic anhydride by ethyl alcohol can be represented by the following balanced equation:
$(C H_{3} C O)_{2} O A + C_{2} H_{5} O H B ⟶ {C H}_{3} C O O C_{2} H_{5} + {C H}_{3} C O O H$
When the reaction is carried out in dilute hexane, rate is $k [A] [B]$ . When ethyl alcohol is the solvent, rate is $k [A]$ .Explain the difference.

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