The ex - radii r1,r2,r3 of Δ ABC are in H.P . Show that its sides a, b, c are in A.P
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Solution
Since r1,r2,r3 are in H.P. it follows that or s−aS,s−bS,s−cS are in A.P. Hence 2(s−b)S=s−aS+s−cS or -2b = -a - c or b = 12 (a + c) Hence a,b,c are in A.P.