Question

The excess pressure due to surface tension in a spherical liquid drop of radius r is directly proportional to

• A. r
• B. r²
• C. r^-1
• D. r^-2

Answer 1

The correct option is C

r^-1

$\Delta p=\frac{2T}{r}\Rightarrow \Delta p\alpha \frac{1}{r}\Rightarrow \Delta p\alpha r^{-1}$