CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The excess pressure inside a soap bubble is twice the excess pressure inside a second soap bubble. The volume of the first bubble is n times the volume of the second where n is
(a) 4
(b) 2
(c) 1
(d) 0.125

Open in App
Solution

Correct option: (d)
Let the excess pressure inside the second bubble be P.
ā€‹∴ Excess pressure inside the first bubble = 2P
Let the radius of the second bubble be R.
Let the radius of the first bubble be x.

Excess pressure inside the 2nd soap bubble:P = 4SR...(1)Excess pressure inside the 1st soap bubble:2P = 4SxFrom (1), we get:24SR=4Sxx = R2Volume of the first bubble = 43πx3Volume of the second bubble = 43πR343πx3=n43πR3x3=nR3R23=nR3n=18=0.125

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Surface Tension
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon