wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The exhaustive set of values of b such that {In(x22x+2)}2+bIn(x22x+2)+1>0x>1 is

A
(3,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(1,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(2,)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(2,)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C (2,)
Let t=In(x22x+2)=In[(x1)2+1]
Then t > 0 x > 1. So we need to find b such that t2 + bt + 1 > 0 t > 0
b>(t+1t)b>2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Inverse of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon