The expanded form of (3x−5)3 is
(a) 27x3+135x2+225x−125
(b) 27x3+135x2−225x−125
(c) 27x3−135x2+225x−125
(d) none of these
The correct option is (c) 27x3−135x2+225x−125
We have
(3x−5)3
=3x3−53−3×3x×5(3x−5) [∵(a−b)3=a3−b3−3ab(a−b)]
=27x3−125−45x(3x−5)
=27x3−125−135x2+225x
=27x3−135x2+225x−125