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Question

The expansion (1+x)n = 1 + nx + n(n−1)2!(x)2........... is valid if |x| > 1.


A

True

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B

False

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Solution

The correct option is B

False


It is valid only if |x| < 1

The expansion (1+x)n = 1 + nx + n(n1)2!(x)2......... has infinite number of terms. If |x| > 1, the value on the R.H.S might become infinite. L.H.S. will always be finite if n is finite. E.g.: consider (1+1)n = 1 + n + n(n1)2!........ L.H.S. is 2n but R.H.S. will be infinite. So we want |x| < 1.


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