The expansion of the bracket $(x + y)^{2}$ would be equal to $x^{2} + y^{2} + 2 x y$ .

Yes

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Solution

The correct option is A Yes

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Similar questions

x - y + 2 z)^{2}

x^{2} + y^{2} = (x + y)^{2} - 2 x y

x^{2} + y^{2} = (x - y)^{2} + 2 x y

(x + y)^{2} = x^{2} + y^{2} + 2 x y

x \neq \pm y

\frac{x^{2} - y^{2}}{x^{2} + 2 x y + y^{2}} : \frac{x - y}{x + y}

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