Question

The experimental and calculated dipole moment of $HI$ are $0.127\times {10}^{-29}$ C.m and $2.57\times {10}^{-29}$ C.m. What is the percentage ionic character?

• A. 10%
• B. 3.5%
• C. 7.6%
• D. 4.9%

Answer 1

The correct option is D 4.9%

Experimental dipole moment of $HI$ = $0.127\times {10}^{-29}$ cm

Calculated dipole moment of $HI$ = $2.57\times {10}^{-29}cm$

% ionic character= $\frac{\mu exp\times 100}{\mu calculated}=\frac{0.127\times {10}^{-29}}{2.57\times {10}^{-29}}\times 100$

= $0.0494\times 100$

=$4.94$