Question

The experimental bond moment (approximate, in Debye) of the X - Y bond, if electronegativity of element X and Y is 1 and 2.5, respectively, and bond length is 3.92 $A^0$ is:

Answer 1

First calculate the electronegativity difference.
$\Delta X=E.N{.}_y-E.N{.}_X=2.5-1.0=1.5$
Now calculate the percentage ionic character.
Percentage ionic character = $16\Delta X+3.5(\Delta X{)}^2$
Calculate the experimental bond moment (approximate, in debye) of the X - Y bond.
Percentage ionic character = $\frac{{\mu }_{exp}}{{\mu }_{theo}}\times 100$
16(1.5) + 3.5 $(1.5{)}^2$ = $\frac{{\mu }_{exp}\times \frac{1}{3}\times {10}^{29}}{1.6\times {10}^{-19}\times 3.92\times {10}^{-10}}\times 100$
${\mu }_{exp}$= 5.99 = 6
Hence, the experimental bond moment (approximate, in debye) of the X - Y bond is 6.