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Byju's Answer
Standard XII
Chemistry
Rate Constant
The experimen...
Question
The experimental data for the reaction
2
A
+
B
2
→
2
A
B
is as follows
[A]
[
B
2
]
Rate
0.50M
0.50M
1.6
×
10
−
4
s
−
1
0.50M
1.00M
3.2
×
10
−
4
s
−
1
1.00M
1.00M
3.2
×
10
−
4
s
−
1
The most probable equation for the rate of the reaction is :
A
k
[
B
2
]
[
A
]
2
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B
k
[
B
2
]
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C
k
[
A
]
2
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D
k
[
A
]
[
B
]
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Solution
The correct option is
B
k
[
B
2
]
When the concentration of
B
2
is doubled, the rate is doubled so the order with respect to
B
2
is one.
When the concentration of A is doubled, the rate remains unaltered so the order with respect to
A
is 0.
So,
−
d
x
d
t
=
k
[
A
]
o
[
B
2
]
1
=
k
[
B
2
]
Option B is correct.
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Similar questions
Q.
The experimental data for the reaction,
2
A
+
B
2
⟶
2
A
B
, is as follows:
Expt. No.
[
A
]
(
m
o
l
L
−
1
)
[
B
2
]
(
m
o
l
L
−
1
)
Rate
(
m
o
l
L
−
1
s
−
1
)
1.
0.50
0.50
1.6
×
10
−
4
2.
0.50
1.00
3.2
×
10
−
4
3.
1.00
1.00
3.2
×
10
−
4
Write the most probable equation for the rate of reaction giving reason for your answer.
Q.
The experimental data for the reaction;
2
A
+
B
2
→
2
A
B
, are as follows. The probable rate expression is:
[A]
[
B
2
]
Rate
m
o
l
l
i
t
r
e
−
1
m
o
l
l
i
t
r
e
−
1
m
o
l
l
i
t
r
e
−
1
s
e
c
−
1
0.50
0.50
1.6
×
10
−
4
0.50
1.0
3.2
×
10
−
4
1.00
1.0
3.2
×
10
−
4
Q.
The experimental data for the reaction
2
A
+
B
2
⟶
2
A
B
, is:
Expt. No.
[
A
]
[
B
2
]
Rate
(
m
o
l
L
−
1
s
−
1
)
1.
0.50
0.50
1.6
×
10
−
4
2.
0.50
1.00
3.2
×
10
−
4
3.
1.0
1.00
3.2
×
10
−
4
The rate equation for the above data is:
Q.
The experimental data for the reaction,
2
A
+
B
2
→
2
A
B
are as follows. Write probable rate expression;
[
A
]
m
o
l
l
i
t
r
e
−
1
[
B
2
]
m
o
l
l
i
t
r
e
−
1
R
a
t
e
×
10
4
m
o
l
l
i
t
r
e
−
1
sec
−
1
0.50
0.50
1.6
0.50
1.00
3.2
1.00
1.00
3.2
Q.
The kinetic datas for the reaction :
2
A
+
B
2
→
2
A
B
are as given below:
[
A
]
m
o
l
L
−
1
[
B
2
]
m
o
l
L
−
1
Rate
m
o
l
L
−
2
m
i
n
−
1
2
1.0
2.5
×
10
−
3
1.0
1.0
2.5
×
10
−
3
2
2.0
1
×
10
−
2
Hence the order of reaction w.r.t
A
and
B
2
are _____ respectively.
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