The exponential form of ${log}_{10} 0.001 = - 3$ is ..........

{(0.001)}^{10} = - 3

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{(- 3)}^{10} = 0.001

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{(10)}^{3} = - 0.001

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{(10)}^{- 3} = 0.001

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Solution

The correct option is D ${(10)}^{- 3} = 0.001$
$D$ is exponential form
We can write that from ${log}_{b} a = c ⟹ a = b^{c}$

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