The exponential form of ${log}_{2} 16 = 4$ is

2^{4} = 16

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4^{2} = 16

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2^{16} = 4

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4^{16} = 2

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Solution

The correct option is C $2^{4} = 16$
Since, ${log}_{2} 16 = 4$
$⟹ log$ of $16$ to the base $2$ is $4$
$\Rightarrow 16 = 2^{4}$
Hence, A is the correct option.

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Similar questions

Simplify and write in exponential form:
$4^{3} \times 4^{- 2} \times 16^{2}$

4^{3}

4^{- 2}

16^{2}

Simplify and write the expression in exponential form: $4^{3}$ x $4^{- 2}$ x $16^{2}$

Express the exponential form with prime number as base.

(1) 4

(2) 8

(3) 16

(4) 49

(5) 81

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