The exponential Fourier series coefficient of a continuous time periodic signal is Ck, ifC−1 = j2,C−3=j0.1, the time domain signal is real and odd and Ck = 0 for |K |> 3. Then the signal has
A
power equal to 10.02
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B
energy equal to 5.01
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C
power equal to 8.02
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D
energy equal to 10.2
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Solution
The correct option is C power equal to 8.02 Since signal is periodic it will be power signal and signal is odd so Ck value will be odd .
so Ck=−C−k
Power of signal =∞∑k=−∞|Ck|2=3∑k=−3|Ck|2 C0 = 0 as signal is odd and C1=−C−1 , C3=−C−3
so Power =2(2)2 +2(0.1)2 =8+0.02=8.02