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Question

The expression, 3[sin4(3π2α)+sin4(3π+α)]2[sin6(π2+α)+sin6(5πα)] when simplified is equal to

A
0
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B
1
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C
3
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D
sin4α+cos6α
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Solution

The correct option is B 1

Simplifying we get
3[cos4α+sin4α]2[cos6α+sin6α]
=3[12cos2α.sin2α]2[13cos2α.sin2α]
=36cos2α.sin2α2+6cos2α.sin2α
=32
=1


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