wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The expression, 3[sin4(3π2α)+sin4(3π+α)]2[sin6(π2+α)+sin6(5πα)] when simplified is equal to

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
sin4α+cos6α
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1

Simplifying we get
3[cos4α+sin4α]2[cos6α+sin6α]
=3[12cos2α.sin2α]2[13cos2α.sin2α]
=36cos2α.sin2α2+6cos2α.sin2α
=32
=1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Functions in a Unit Circle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon