The expression 3[sin4(3π2−α)+sin4(3π+α)]−2[sin6(π2+α)+sin6(5π−α)] is
The expression 3[sin4(3π2−α)+sin4(3π+α)]−2[sin6(π2+α)+sin6(5π+α)] is equal to
3[sin4(3π2−α)+sin4(3π+α)] - [sin6(π2+α)+sin6(5π−α)] =