The expression $3 (sin x - cos x)^{4} + 6 (sin x + cos x)^{2} + 4 ({sin}^{6} x + {cos}^{6} c)$ is equal to

10

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11

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12

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13

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Solution

The correct option is C $13$
$3 (sin x - cos x)^{4} + 6 (sin x + cos x)^{2} + 4 ({sin}^{6} x + {cos}^{6} c)$
$= 3 (1 + 4 {sin}^{2} x {cos}^{2} x - 4 sin x cos x) + 6 (1 + 2 sin x cos x) + 4 (1 - 3 {sin}^{2} x {cos}^{2} x) = 3 + 6 + 4 = 13$ .

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Similar questions

3 (sin x - cos x)^{4} + 4 ({sin}^{6} x + {cos}^{6} x) + 6 (sin x + cos x)^{2}

3 (s i n x - c o s x)^{4} + 6 (s i n x + c o s x)^{2} + 4 (s i n^{6} x + c o s^{6} x)

3 (sin x - cos x)^{4} + 6 (sin x + cos x)^{2} + 4 ({sin}^{6} x + {cos}^{6} x)

3 {(sin x - cos x)}^{4} + 4 ({sin}^{6} x + {cos}^{6} x) + 6 {(sin x + cos x)}^{2} = 13

3 {(sin x - cos x)}^{4} + 6 {(sin x + cos x)}^{2} + 4 ({sin}^{6} x + {cos}^{6} x) = 13

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