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Question

The expression a2+baba can be factorise as

A
(ab)(a+1)
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B
(a+b)(a1)
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C
(ab)(a1)
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D
(a+b)(a+1)
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Solution

The correct option is C (ab)(a1)
The expression a2+baba can be written as
a2ab+ba
a(ab)1(ab) [Taking 'a' common]
(ab)(a1) [Taking (a-b) common]
Henve the factorize form is
(ab)(a1)

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