The expression cos2ϕ+cos2(a+ϕ)−2cosacosϕcos(a+ϕ) is independent is
A
ϕ
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B
a
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C
both a and ϕ
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D
none of a and ϕ
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Solution
The correct option is Aϕ
The given expression is
equal to cos2ϕ+cos2(a+ϕ)−[cos(a+ϕ)+cos(a−ϕ)]cos(a+ϕ) =cos2ϕ−cos(a+ϕ)cos(a−ϕ) =cos2ϕ−(cos2ϕ−sin2a)=sin2a which is independent of ϕ.