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Byju's Answer
Standard XII
Physics
Introduction
The expressio...
Question
The expression
1
√
4
x
+
1
⎡
⎣
[
1
+
√
4
x
+
1
2
]
7
−
[
1
+
√
4
x
+
1
2
]
7
⎤
⎦
is a polynomial in x of degree ?
A
0
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B
4
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C
7
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D
Not defined
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Solution
The correct option is
D
Not defined
let
√
4
x
+
1
=
y
Now
1
y
[
[
1
+
y
2
]
7
−
[
1
+
y
2
]
7
]
now let
[
1
+
y
2
]
=
m
hence
1
y
[
m
7
−
m
7
]
=
0
Suggest Corrections
0
Similar questions
Q.
The expression
1
√
4
x
+
1
[
[
1
+
√
4
x
+
1
2
]
7
−
[
1
−
√
4
x
+
1
2
]
7
]
is a polynomial in x of degree
Q.
The degree of the polynomial
1
√
4
x
+
1
⎡
⎣
(
1
+
√
4
x
+
1
2
)
7
−
(
1
−
√
4
x
+
1
2
)
7
⎤
⎦
is
Q.
Enter 1 for True and 0 for False
∫
(
x
+
3
)
√
3
−
4
x
−
x
2
d
x
=
−
1
3
(
3
−
4
x
−
x
2
)
3
/
2
+
(
x
+
2
)
√
3
−
4
x
−
x
2
2
+
7
2
sin
−
1
(
x
+
2
)
√
7
+
C
Q.
The value of the polynomial
4
x
2
+
3
x
−
7
at
x
=
1
is:
Q.
The degree of the polynomial
1
√
4
x
+
1
⎡
⎣
(
1
+
√
4
x
+
1
2
)
7
−
(
1
−
√
4
x
+
1
2
)
7
⎤
⎦
is
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