No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
sin2Θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
cos2Θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D 1 cos4θ−sin4θ+2sin2θ=(cos2θ)2−(sin2θ)2+2sin2θ Now using a2−b2=(a+b)(a−b) we have (cos2θ−sin2θ)(cos2θ+sin2θ)+2sin2θ Now cos2θ+sin2θ=1 Now we have 1−2sin2θ+2sin2θ=1