Question

The expression $(p^{-2x}{q}^{3y}{)}^6÷{\left(p^3{q}^{-1}\right)}^{-4x}$ after simplification becomes

• A. independent of p, but not of q
• B. independent of q, but not of p
• C. independent of both p and q
• D. dependent on both p and q but independent of x and y

Answer 1

The correct option is A independent of p, but not of q

$\frac{{\left(p^{-2x}{q}^{3y}\right)}^6}{{\left(p^3{q}^{-1}\right)}^{-4x}}=\frac{p^{-12x}{q}^{18y}}{p^{-12x}{q}^{4x}}=q^{18y-4x}$