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Question

The expression E=secθ+tanθ1tanθsecθ+1 can be simplified to -


A

cosθ/(1-sinθ)

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B

sinθ/(1-cosθ)

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C

(1-sinθ)/cosθ

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D

(1-cosθ)/sinθ

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E

None of these

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Solution

The correct option is A

cosθ/(1-sinθ)


We write the 1 in the numerator as (sec2θ - tan2θ) -

E=secθ+tanθ(sec2θtan2θ)tanθsecθ+1=secθ+tanθ(secθ+tanθ)(secθtanθ)1secθ+tanθ=(secθ+tanθ)(1secθ+tanθ)1secθ+tanθ=secθ+tanθ=1secθtanθ=cosθ1sinθ


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