The expression for an AM voltage is e-51-0-6cos100- tcos5-106- t volt- The peak value of carrier wave is -

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Alternating Current Applied to an Inductor

The expressio...

Question

The expression for an AM voltage is
$e = 5 (1 + 0.6 cos 100 π t) cos 5 \times 10^{6} π t v o l t .$ . The peak value of carrier wave is :

30 V

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Solution

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e = 5 (1 + 0.6 cos 100 π t cos 5 \times 10^{6} π t) v o l t .

e = 5 (1 + 0.6 cos 100 π t) cos 5 \times 10^{6} π t v o l t .

e = 5 (1 + 0.6 cos 100 π t) cos 5 \times 10^{6} π t v o l t .

e = 10 (1 + 0.8 cos 2000 π t) cos 3 \times 10^{6} π t v o l t

20 V

30 V

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