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Byju's Answer
Standard XII
Physics
Self Induction
The expressio...
Question
The expression for an AM voltage is
e
=
5
(
1
+
0.6
cos
100
π
t
)
cos
5
×
10
6
π
t
v
o
l
t
.
. The frequency of audio signal is :
A
1000
H
z
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B
5000
H
z
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C
50
H
z
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D
250
H
z
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Solution
The correct option is
C
50
H
z
Comparing the given equation with the standard equation,
e
=
E
c
(
1
+
m
a
cos
ω
m
t
)
cos
ω
c
t
⟹
ω
m
=
100
π
2
π
=
50
H
z
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0
Similar questions
Q.
The expression for an AM voltage is
e
=
5
(
1
+
0.6
cos
100
π
t
cos
5
×
10
6
π
t
)
v
o
l
t
.
. Frequencies of sideband is :
Q.
The expression for an AM voltage is
e
=
5
(
1
+
0.6
cos
100
π
t
)
cos
5
×
10
6
π
t
v
o
l
t
.
. The peak value of carrier wave is :
Q.
The expression for an AM voltage is
e
=
5
(
1
+
0.6
cos
100
π
t
)
cos
5
×
10
6
π
t
v
o
l
t
.
. The percentage of modulation is :
Q.
An amplitude modulated voltage is expressed as
e
=
10
(
1
+
0.8
cos
2000
π
t
)
cos
3
×
10
6
π
t
v
o
l
t
. The bandwidth of modulated signal is :
Q.
An amplitude modulated voltage is expressed as
e
=
10
(
1
+
0.8
cos
2000
π
t
)
cos
3
×
10
6
π
t
v
o
l
t
. The depth of modulation is :
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