The expression for kinetic energy is :

\frac{1}{2} m v

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\frac{1}{3} m v^{2}

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\frac{1}{2 m} v^{2}

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\frac{1}{2} m v^{2}

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Solution

The correct option is C $\frac{1}{2} m v^{2}$
The kinetic energy of a body is the energy by virtue of its motion.
$K . E = \frac{1}{2} m v^{2}$
where $m$ is mass and $v$ is velocity.

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Similar questions

K . E = \frac{1}{2} m v^{2}

\frac{1}{2} M V^{2} [1 + \frac{K^{2}}{R^{2}}]

K E = \frac{1}{2} m v^{2}

\to v = v e l o c i t y

\to a =

K = \frac{1}{2} m v^{2} =

[\begin{matrix} K = \frac{1}{2} m v^{2} = \frac{1}{2} m (\to v \cdot \to v) \end{matrix}]

200 g

3^i - 5^j + 4^k m / s

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