The expression 1-13-1-14- 1-15-1-1n simplifies to-

The correct option is A n+13 (1+13),(1+14),(1+15) (1+1n) a_n amp;=3+(n 1) 1 amp;=3+n 1 amp;=2+n amp; 1+1/n+2 ⇒ am ...

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Definition of Relations

The expressio...

Question

The expression $(1 + \frac{1}{3}), (1 + \frac{1}{4}), (1 + \frac{1}{5}) . . . (1 + \frac{1}{n})$ simplifies to:

\frac{n + 1}{3}

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\frac{n}{n + 1}

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\frac{3}{n}

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1 + \frac{1}{3} . \frac{1}{4} . \frac{1}{5} . . . \frac{1}{n}

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n \in N

n

\frac{1}{1. (n - 1)!} + \frac{1}{3! . (n - 3)!} + \frac{1}{5! . (n - 5)!} + . . . . . . + \frac{1}{(n - 1)! 1!} =

n \in N

\frac{1}{1! \cdot (n - 1)!}

\frac{1}{3! \cdot (n - 3)!}

\frac{1}{5! \cdot (n - 5)!}

\frac{1}{(n - 1)! 1!}

$\frac{1}{1! (n - 1)!}$ + $\frac{1}{3! (n - 3)!}$ + $\frac{1}{5! (n - 5)!}$ + ....... =

\frac{1}{1! \cdot (n - 1)!} + \frac{1}{3! \cdot (n - 3)!} + \frac{1}{5! \cdot (n - 5)!} + . . . +

n

\frac{1}{| 1 - | n - 1 - ---- -} + \frac{1}{| 3 - | n - 3 - ---- -} + \frac{1}{| 5 - | n - 5 - ---- -} + . . . . + \frac{1}{| n - 1 - ---- - | 1 -} = \frac{2^{n - 1}}{| n - -}

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