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Question

The expression (1+13),(1+14),(1+15)...(1+1n) simplifies to:

A
n+13
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B
nn+1
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C
3n
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D
1+13.14.15...1n
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Solution

The correct option is A n+13
(1+13),(1+14),(1+15)(1+1n)
an=3+(n1)1=3+n1=2+n1+1n+2n+2+1n+2=n+3n+2 where nNN is natural number

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