The expression $(m - n)^{2}$ would be equal to

2 m^{2} + 2 m n + n^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m^{2} - 2 m n + n^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

m^{2} + 2 m n - n^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m^{2} - m n + n^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $m^{2} - 2 m n + n^{2}$
$(m - n)^{2} = (m - n) \times (m - n)$
$= m \times (m - n) - n \times (m - n)$
$= (m^{2} - m n) + (- m n + n^{2})$
$= m^{2} - 2 m n + n^{2}$

Suggest Corrections

Similar questions

(m + n)^{2}

(m + n) \times (m - n)

(\frac{m + \sqrt{m^{2} - n^{2}}}{m - \sqrt{m^{2} - n^{2}}} - \frac{m - \sqrt{m^{2} - n^{2}}}{m + \sqrt{m^{2} - n^{2}}}) \frac{n^{2}}{4 m \sqrt{m^{2} - n^{2}}}

(3 p + q) \times (3 p - q)

(x + y) (x - y)

x^{2} - y^{2}

Join BYJU'S Learning Program