The expression m - n - m - n would be equal to-

(m + n) × (m n) nbsp; Firstly outside terms nbsp; (m + n) × (m n) = m × (m n) + n × (m n) = m^2 mn + nm + n^2 = m^2 + mn nm + n^2 We know mn n ...

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Standard VIII

Mathematics

Algebraic Identity: (x + y)(x - y)

The expressio...

Question

The expression $(m + n) \times (m - n)$ would be equal to?

m^{2} + n^{2}

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m^{2} - n^{2}

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2 m^{2} - n^{2}

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m^{2} - 2 n^{2}

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Solution

The correct option is B $m^{2} - n^{2}$
$(m + n) \times (m - n)$
Firstly outside terms
$(m + n) \times (m - n) = m \times (m - n) + n \times (m - n)$
$= m^{2} - m n + n m + n^{2}$
$= m^{2} + m n - n m + n^{2}$
We know $m n - n m = 0$
$= m^{2} - n^{2}$

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The expression (m+n)×(m−n) would be equal to?

The correct option is B m2−n2 (m+n)×(m−n) Firstly outside terms (m+n)×(m−n)=m×(m−n)+n×(m−n) =m2−mn+nm+n2 =m2+mn−nm+n2 We know mn−nm=0 =m2−n2

The expression $(m + n) \times (m - n)$ would be equal to?

The correct option is B $m^{2} - n^{2}$
$(m + n) \times (m - n)$
Firstly outside terms
$(m + n) \times (m - n) = m \times (m - n) + n \times (m - n)$
$= m^{2} - m n + n m + n^{2}$
$= m^{2} + m n - n m + n^{2}$
We know $m n - n m = 0$
$= m^{2} - n^{2}$