The expression obtained by multiplying (7x−4x2+2x3−5) with (3x−2) is:
6x4−16x3+29x2−29x+10
(7x−4x2+2x3−5)×(3x−2)
=3x×(7x−4x2+2x3−5)−2×(7x−4x2+2x3−5)
=21x2−12x3+6x4−15x−14x+8x2−4x3+10
=29x2−16x3+6x4−29x+10
=6x4−16x3+29x2−29x+10 (Rearranging the terms)