Question

The expression of only one of parental characters in $F_1$ is not applicable for one gene or two interaction showing $F_2$ progeny with
A. Two phenotypes and three genotypes w.r.t. plant height in pea.
B. Four phenotypes and nine genotypes w.r.t. plant height and flower colour in pea.
C. Two phenotypes and two genotypes in test cross w.r.t. plant height in pea.
D.Three phenotypes and three genotypes w.r.t. flower colour in snapdragon.
E. Five phenotypes and nine genotypes w.r.t. keral colour in wheat.

• A. B and D
• B. A, D and E
• C. D and E
• D. B,C and D

Answer 1

The correct option is C D and E

The expression of only one of parental characters in F1 is applicable for one gene or two interaction showing F2 progeny only if they follow the Mendelian pattern of inheritance. . Two phenotypes and three genotypes w.r.t. plant height in pea, Four phenotypes and nine genotypes w.r.t. plant height and flower colour in pea and two phenotypes and two genotypes in test cross w.r.t. plant height in pea, all follow the properties of Mendelian Inheritance. However, Three phenotypes and three genotypes w.r.t. flower colour in snapdragon shows incomplete dominance and Five phenotypes and nine genotypes w.r.t. kernel colour in wheat shows polygenic inheritance. Both of them do not follow the Mendelian laws of genetics and are variants of the law.

So the correct option is 'D and E'.