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Standard XII

Chemistry

Emission and Absorption Spectra

The expressio...

Question

The expression of Rydberg constant is:

\frac{2 π^{2} m h^{2} c}{(e^{2} / 4 π ε_{0})^{2}}

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\frac{2 π^{2} m (e^{2} / 4 π ε_{0})^{2}}{h^{3} c}

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\frac{(e^{2} / 4 π ε_{0})^{2}}{2 π^{2} m h^{3} c}

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\frac{2 π^{2} m h^{3} c}{e^{2} / 4 π ε_{0}}

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Solution

The correct option is B $\frac{2 π^{2} m (e^{2} / 4 π ε_{0})^{2}}{h^{3} c}$
Rydberg constant is given by expression, $R = \frac{2 π^{2} m (e^{2} / 4 π ε_{0})^{2}}{h^{3} c}$ .

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A physical quantity of the dimension of length that can be formed out of c, G and $\frac{e^{2}}{4 π ε_{0}}$ is [c is velocity of light, G is universal constant of gravitation and e is charge]

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Q. Match

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and select the correct answer using the code given below:

\begin{matrix} List I & List II (A) & If E_{1} and E_{2} be mutually exclusive events, then & 1 & E_{1} \cap E_{2} = E_{1} (B) & If E_{1} and E_{2} are mutually exclusive and exhaustive events, then & 2 & (E_{1} - E_{2}) \cup (E_{1} \cap E_{2}) = E_{1} (C) & If E_{1} and E_{2} have common outcomes, then & 3 & E_{1} \cap E_{2} = ϕ, E_{1} \cup E_{2} = S (D) & If E_{1} and E_{2} are events such that E_{1} \subset E_{2}, then & 4 & E_{1} \cap E_{2} = ϕ \end{matrix}

Which of the following is the only CORRECT combination?

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The expression of Rydberg constant is:

The correct option is B 2π2m(e2/4πε0)2h3cRydberg constant is given by expression, R=2π2m(e2/4πε0)2h3c.

The correct option is B $\frac{2 π^{2} m (e^{2} / 4 π ε_{0})^{2}}{h^{3} c}$
Rydberg constant is given by expression, $R = \frac{2 π^{2} m (e^{2} / 4 π ε_{0})^{2}}{h^{3} c}$ .