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Standard XII

Chemistry

Molality

The expressio...

Question

The expression relating molality ( $m$ ) and mole fraction ( $x_{2}$ ) of solute in a solution is:

x_{2} = \frac{m M_{1}}{1 + m M_{1}}

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x_{2} = \frac{m M_{1}}{1 - m M_{1}}

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x_{2} = \frac{1 + m M_{1}}{m M_{1}}

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x_{2} = \frac{1 - m M_{1}}{m M_{1}}

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Solution

The correct option is A $x_{2} = \frac{m M_{1}}{1 + m M_{1}}$
Let W $_{1}$ and M $_{1}$ denote weight and molecular weight of solvent respectively.
Molality m= $\frac{n_{2}}{W_{2}}$
Therefore $n_{2} = m W_{1}$
$x_{2} = \frac{n_{2}}{n_{1} + n_{2}}$ = $\frac{m W_{1}}{\frac{W_{1}}{M_{1}} + m W_{1}}$ = $\frac{m M_{1}}{1 + m M_{1}}$

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The expression relating molality (m) and mole fraction (x2) of solute in a solution is:

The correct option is A x2=mM11+mM1Let W1 and M1 denote weight and molecular weight of solvent respectively.Molality m=n2W2 Therefore n2=mW1x2=n2n1+n2 = mW1W1M1+mW1 = mM11+mM1

The expression relating molality ( $m$ ) and mole fraction ( $x_{2}$ ) of solute in a solution is: