1
Question
The expression ∼(p∨q)∨(∼p∧q) is logically equivalent to
The expression ∼(p∨q)∨(∼p∧q) is logically equivalent to
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Solution
The correct option is C ∼p
∼(p∨q)∨(∼p∧q)
=(∼p ∧∼q)∨(∼p∧q)
= ∼p∧(∼q∨q)
= ∼p∧T, where T is true.
= ∼p
∼(p∨q)∨(∼p∧q)
=(∼p ∧∼q)∨(∼p∧q)
= ∼p∧(∼q∨q)
= ∼p∧T, where T is true.
= ∼p
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