The expression that can represent the area of a square is

x^{2} - 4 x - 4

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x^{2} - 7 x + 16

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x^{2} + 6 x + 9

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x^{2} - 10 x + 36

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Solution

The correct option is C $x^{2} + 6 x + 9$
$x^{2} + 6 x + 9 = (x)^{2} + 2 (x) (3) + 3^{2} = (x + 3)^{2}$

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\frac{x^{2} + 4 x + 4}{25} - \frac{y^{2} - 6 x + 9}{16} = 1

\frac{6}{7 x - 21} - \frac{1}{x^{2} - 6 x + 9} + \frac{1}{x^{2} - 9} = 0

\frac{x^{2} - 3 x + 2}{x^{2} - 5 x + 6} \div \frac{x^{2} - 5 x + 4}{x^{2} - 7 x + 12}

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