The expression $x^{2} + 2 b x + c$ has the positive value, if

b^{2} - 4 c > 0

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b^{2} - c < 0

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c^{2} > b

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b^{2} > c

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Solution

The correct option is C $c^{2} > b$
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Similar questions

a = 1

b = - 1

c = 0

(a^{2} - b^{2}) + (c^{2} - b^{2}) + (a^{2} - c^{2})

x^{2} + b x + c = 0

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

The condition for the equation $x^{2} + b x + c = 0$ to have real roots is ____.

x^{2} + b x - c = 0

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