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Byju's Answer
Standard XI
Mathematics
Modulus of a Complex Number
The expressio...
Question
The expression
(
x
2
+
y
2
)
4
is equal to
A
(
x
4
−
2
x
2
y
2
+
y
4
)
2
+
(
4
x
3
y
+
4
x
y
3
)
2
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B
(
x
4
+
6
x
2
y
2
−
y
4
)
2
+
(
4
x
3
y
−
4
x
y
3
)
2
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C
(
x
4
−
6
x
2
y
2
+
y
4
)
2
+
(
4
x
3
y
−
4
x
y
3
)
2
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D
None of these
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Solution
The correct option is
C
(
x
4
−
6
x
2
y
2
+
y
4
)
2
+
(
4
x
3
y
−
4
x
y
3
)
2
(
x
2
+
y
2
)
4
=
|
x
+
i
y
|
8
=
∣
∣
(
x
+
i
y
)
2
∣
∣
4
=
∣
∣
(
x
2
−
y
2
)
+
2
i
x
y
∣
∣
4
=
∣
∣
[
(
x
2
−
y
2
)
+
2
i
x
y
]
2
∣
∣
2
=
∣
∣
(
x
2
−
y
2
)
2
+
(
2
i
x
y
)
2
+
2
(
x
2
−
y
2
)
(
2
i
x
y
)
∣
∣
2
=
∣
∣
x
4
+
y
4
−
2
x
2
y
2
−
4
x
2
y
2
+
i
(
4
x
3
y
−
4
x
y
3
)
∣
∣
2
=
∣
∣
x
4
+
y
4
−
6
x
2
y
2
+
i
(
4
x
3
y
−
4
x
y
3
)
∣
∣
2
=
(
x
4
−
6
x
2
y
2
+
y
4
)
2
+
(
4
x
3
y
−
4
x
y
3
)
2
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0
Similar questions
Q.
The expression
(
x
2
+
y
2
)
4
is equal to
Q.
Assertion :Tangents drawn from any point on the circle
x
2
+
y
2
=
13
to the ellipse
x
2
9
+
y
2
4
=
1
are at right angles. Reason: Equation of the auxilliary circle of the ellipse
x
2
13
+
y
2
4
=
1
is
x
2
+
y
2
=
13
Q.
If
l
is the length of the intercept made by a common tangent to the circle
x
2
+
y
2
=
16
and the ellipse
x
2
25
+
y
2
4
=
1
on the coordinate axes, then
3
l
2
28
is equal to
Q.
Prove that
(
x
2
+
y
2
)
4
=
(
x
4
−
6
x
2
y
2
+
y
4
)
2
+
(
4
x
3
y
−
4
x
y
3
)
2
.
Q.
Minimum value of the expression
x
2
−
2
x
+
3
for
x
∈
[
2
,
5
)
is equal to -
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Modulus of a Complex Number
Standard XI Mathematics
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