The extension in a string obeying Hooke's law v is x. The speed of sound in the stretched string is v. If the extension in the string is increased to 1.5x, the speed of sound will be
A
1.22v
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B
0.61v
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C
1.50v
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D
0.75v
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Solution
The correct option is B1.22v Speed of sound in stretched string v=¯¯¯¯Tμ.....(i) where T is the tension in the string and μ is mass per unit length. According to Hooke's law, F∝X ∴T∝X .... (ii) From Eqs. (i) and (ii) v∝ ∴v′=¯¯¯¯¯¯¯¯¯¯¯1.5V=1.22V.