The extent of crystal field splitting in octahedral complex of the given metal with particular weak field ligand are such that :

F e (I I I) < C r (I I I) < R h (I I I) < I r (I I I)

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C r (I I I) < F e (I I I) < R h (I I I) < I r (I I I)

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I r (I I I) < R h (I I I) < F e (I I I) < C r (I I I)

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F e (I I I) = C r (I I I) < R h (I I I) < I r (I I I)

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Solution

The correct option is A $F e (I I I) < C r (I I I) < R h (I I I) < I r (I I I)$
The trend of $+ 3$ charged ion with weak field ligand is $F e (I I I) < C r (I I I) < R h (I I I) < I r (I I I)$ , so is the trend of crystal field splitting.

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The extent of crystal field splitting in octahedral complex of the given metal with particular weak field ligand are such that :

The correct option is A Fe(III)<Cr(III)<Rh(III)<Ir(III)The trend of +3 charged ion with weak field ligand is Fe(III)<Cr(III)<Rh(III)<Ir(III), so is the trend of crystal field splitting.

The correct option is A $F e (I I I) < C r (I I I) < R h (I I I) < I r (I I I)$
The trend of $+ 3$ charged ion with weak field ligand is $F e (I I I) < C r (I I I) < R h (I I I) < I r (I I I)$ , so is the trend of crystal field splitting.