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Question

The exterior angles obtained on producing the base of a triangleABC both ways are 100degree and 120degree. Find all the angles of the triangle.

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Solution

Let ABC be the triangle with BC produced on both sides B and C till E and F respectively.
Angle ABE = 100 degrees
Angle ACF = 120 degrees
angle ABE + angle ABC = 180 degrees
=> 100 degrees+angle ABC=180degrees
=> angle ABC = (180-100) degrees
=> angle ABC = 80 degrees
angle ACF + angle ACB = 180 degrees
=> 120 degrees+angle ACB=180 degrees
=> angle ACB = (180-120) degrees
=> angle ACB = 60 degrees
angle BAC = (180-80-60) degrees
= (180-140) degrees
= 40 degrees
So, the three angles are 80,60,40 degrees.

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