The extraction of which of the following metals involves bessemerisation?

F e

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A g

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A l

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C u

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Solution

The correct option is D $C u$
In a Bessemer converter, copper pyrites are oxidised to $F e O$ and $C u_{2} O$ , FeO is slagged off. $C u_{2} O$ reacts with $C u_{2} S$ left unoxidised to give $C u$ .

$2 C u_{2} S + 3 O_{2} ⟶ 2 C u_{2} O + 2 S O_{2}$
$2 C u_{2} O + C u_{2} S ⟶ 6 C u + S O_{2}$

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Similar questions

C u_{2} S

P b, A u, M g, S n, F e, A l, A g, H g, N a, Z n, C u, C a

C u {S O}_{4}

E_{{C u}^{2 +} / C u}^{o} = 0.34 V

E_{{F e / F e}^{2 +}}^{o} = 0.44 V, E_{{A l / A l}^{3 +}}^{o} = 1.66 V

E_{N i / {N i}^{2 +}}^{o} = 0.25 V, E_{{A g}^{+} / A g}^{o} = 0.80 V

F e

A g^{+} (a q) + e^{-} - > A g (s) E^{\circ} = + 0.80 V

C u^{2 +} (a q) + 2 e^{-} - - > C u (s) E^{\circ} = + 0.34 V

P b^{2 +} (a q) + 2 e^{-} - - > P b (s) E^{\circ} = - 0.13 V

F e^{2 +} (a q) + 2 e^{-} - - > F e (s) E^{\circ} = - 0.44 V

A l^{3 +} (a q) + 3 e^{-} - - > A l (s) E^{\circ} = - 1.66 V

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