The extremities of a diagonal of a parallelogram are the points (1,−2) and (−4,3). If third vertex is (−1,0). Then the co-ordinates of fourth vertex are :
A
(2,1)
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B
(−2,−1)
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C
(−2,1)
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D
noneofthese
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Solution
The correct option is A(2,1) p(−32,12)α−12=−32α=−2β+02=12β=1(2,1)