The extremities of latus rectum of a parabola are (1,1) and (1,−1). Then the equation(s) of the parabola is/are
A
y2=2x−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
y2=1−2x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y2=3−2x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
y2=2x−3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are Ay2=2x−1 Cy2=3−2x Given that the extremities of the latus rectum are (1,1) and (1,−1). Then, 4a=2 or a=12 So, the focus of the parabola is (1,0) Hence, the vertex can be (12,0) or (32,0) Therefore, for the vertex (12,0), the equations of the parabola can be y2=2(x−12) For the vertex (32,0), the equation of parabola y2=−2(x−32) i.e. y2=2x−1 or y2=3−2x