The extremities of the latus rectum of an ellipse x216+y29=1 is
A
(±√7,±94)
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B
(±√9,±165)
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C
(±4,±254)
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D
(±6,±45)
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Solution
The correct option is A(±√7,±94) Given ellipse is of the form x2a2+y2b2=1
Where a=4,b=3
Clearly a>b ⇒e2=1−b2a2=716 ∴e=√74
Coordinates of extremities of latus rectum are given by (±ae,±b2a)≡(±√7,±94)