The ′f′ orbitals are half and completely filled, respectively in lanthanide ions
[Given: Atomic no. Eu, 63; Sm, 62; Tm, 69; Tb, 65; Yb, 70; Dy, 66]
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Solution
+2+3+4Eu4f74f6Tm4f134f12Sm4f64f5Tb4f94f84f7Yb4f144f13Dy4f104f9
Hence, the pair Tb+4Yb+2 have half filled and completely filled f subshells respectively.