The face BC of a prism of refractive index μ=√2 is silvered. Angle ∠BCA=30∘. A light ray incident on the face AC retraces the path. The value of incident angle θ is
A
30∘
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B
45∘
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C
60∘
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D
40∘
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Solution
The correct option is B45∘ The light ray retraces the path if it falls along the normal on the force BC. Angle of refraction in the prism = r ∠D=90∘∴r=90∘−∠CED=90−60=30∘ Applying shell's law, (1)sinθ=√2sin30∘ =√2×12 θ=45∘