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Question

The factor of 5x2−15x−7x+21 is

A
(5x1)(x7)
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B
(5x7)(x3)
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C
(5x+3)(x7)
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D
(5x+7)(x3)
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Solution

The correct option is B (5x7)(x3)
5x222x+21
=5x215x7x+21 (Rewrite 22x as 15x7x to make grouping and factoring easier.)
=5x215x7x+21
=5x(x3)7(x3)
=(5x7)(x3)
Therefore 5x222x+21=(5x7)(x3)

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