The factors of 12 ab -9 a -12-16 b is-are-A- 4 b-3B- 3 a-4C- 3 a-44 b-3D- 3 a-44 b-3

The correct options are A (4b + 3) C (3a + 4)(4b + 3)12ab + 9a + 12 + 16b = 3a × (4b + 3) + 4 × (3 + 4b) We can observe that (4b + 3) is a common factor. The s ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation by Regrouping Terms

The factors o...

Question

The factor(s) of 12ab + 9a + 12 + 16b is/are:

(4b + 3)

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(3a - 4)

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(3a + 4)(4b + 3)

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(3a + 4)(4b - 3)

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Solution

The correct options are
A
(4b + 3)

C (3a + 4)(4b + 3)
12ab + 9a + 12 + 16b = $3 a \times (4 b + 3) + 4 \times (3 + 4 b)$
We can observe that (4b + 3) is a common factor. The simplified expression becomes:
$(4 b + 3) \times (3 a + 4)$
So, 4b + 3 and 3a + 4 are the irreducible factors of the given algebraic expression.

Suggest Corrections

The factor(s) of 12ab + 9a + 12 + 16b is/are:

The correct options are A (4b + 3) C (3a + 4)(4b + 3)12ab + 9a + 12 + 16b = 3a×(4b+3)+4×(3+4b) We can observe that (4b + 3) is a common factor. The simplified expression becomes: (4b+3)×(3a+4) So, 4b + 3 and 3a + 4 are the irreducible factors of the given algebraic expression.